Rhombicuboctahedron

The rhombicuboctahedron may be constructed from a cube by drawing a smaller one in the middle of each face, parallel to the cube's edges. After removing the edges of a cube, the squares may be joined by adding more squares adjacent between them, and the corners may be filled by the equilateral triangles. Another way to construct the rhombicuboctahedron is by attaching two regular square cupolas into the bases of a regular octagonal prism.^[2]

A rhombicuboctahedron may also be known as an expanded octahedronorexpanded cube. This is because the rhombicuboctahedron may also be constructed by separating and pushing away the faces of a cube or a regular octahedron from their centroid (in blue or red, respectively, in the animation), and filling between them with the squares and equilateral triangles. This construction process is known as expansion.^[3] By using all of these methods above, the rhombicuboctahedron has 8 equilateral triangles and 16 squares as its faces.^[4] Relatedly, the rhombicuboctahedron may also be constructed by cutting all edges and vertices of either cube or a regular octahedron, a process known as rectification.^[5]

Cartesian coordinates of a rhombicuboctahedron with an edge length 2 are the permutations of ${\displaystyle \left(\pm \left(1+{\sqrt {2}}\right),\pm 1,\pm 1\right)}$ . ^[6]

The surface area of a rhombicuboctahedron ${\displaystyle A}$  can be determined by adding the area of all faces: 8 equilateral triangles and 10 squares. The volume of a rhombicuboctahedron ${\displaystyle V}$  can be determined by slicing it into two square cupolas and one octagonal prism. Given that the edge length ${\displaystyle a}$ , its surface area and volume is:^[7] $${\displaystyle {\begin{aligned}A&=\left(18+2{\sqrt {3}}\right)a^{2}&\approx 21.464a^{2},\\V&={\frac {12+10{\sqrt {2}}}{3}}a^{3}&\approx 8.714a^{3}.\end{aligned}}}$$ 

The optimal packing fraction of rhombicuboctahedra is given by $${\displaystyle \eta ={\frac {4}{3}}\left(4{\sqrt {2}}-5\right).}$$  It was noticed that this optimal value is obtained in a Bravais latticebyde Graaf, van Roij & Dijkstra (2011).^[8] Since the rhombicuboctahedron is contained in a rhombic dodecahedron whose inscribed sphere is identical to its inscribed sphere, the value of the optimal packing fraction is a corollary of the Kepler conjecture: it can be achieved by putting a rhombicuboctahedron in each cell of the rhombic dodecahedral honeycomb, and it cannot be surpassed, since otherwise the optimal packing density of spheres could be surpassed by putting a sphere in each rhombicuboctahedron of the hypothetical packing which surpasses it.^{[citation needed]}

The dihedral angle of a rhombicuboctahedron can be determined by adding the dihedral angle of a square cupola and an octagonal prism:^[9]

• the dihedral angle of a rhombicuboctahedron between two adjacent squares on both the top and bottom is that of a square cupola 135°. The dihedral angle of an octagonal prism between two adjacent squares is the internal angle of a regular octagon 135°. The dihedral angle between two adjacent squares on the edge where a square cupola is attached to an octagonal prism is the sum of the dihedral angle of a square cupola square-to-octagon and the dihedral angle of an octagonal prism square-to-octagon 45° + 90° = 135°. Therefore, the dihedral angle of a rhombicuboctahedron for every two adjacent squares is 135°.
• the dihedral angle of a rhombicuboctahedron square-to-triangle is that of a square cupola between those 144.7°. The dihedral angle between square-to-triangle, on the edge where a square cupola is attached to an octagonal prism is the sum of the dihedral angle of a square cupola triangle-to-octagon and the dihedral angle of an octagonal prism square-to-octagon 54.7° + 90° = 144.7°. Therefore, the dihedral angle of a rhombicuboctahedron for every square-to-triangle is 144.7°.

A rhombicuboctahedron has the Rupert property, meaning there is a polyhedron with the same or larger size that can pass through its hole.^[10]

The rhombicuboctahedron has the same symmetry as a cube and regular octahedron, the octahedral symmetry ${\displaystyle \mathrm {O} _{\mathrm {h} }}$ .^[11] However, the rhombicuboctahedron also has a second set of distortions with six rectangular and sixteen trapezoidal faces, which do not have octahedral symmetry but rather pyritohedral symmetry ${\displaystyle \mathrm {T} _{\mathrm {h} }}$ , so they are invariant under the same rotations as the tetrahedron but different reflections.^[12] It is centrosymmetric, meaning its symmetric is interchangeable by the appearance of inversion center. It is also non-chiral; that is, it is congruent to its own mirror image.^[13]

The rhombicuboctahedron is an Archimedean solid, meaning it is a highly symmetric and semi-regular polyhedron, and two or more different regular polygonal faces meet in a vertex.^[14] The polygonal faces that meet for every vertex are one equilateral triangle and three squares, and the vertex figure is denoted as ${\displaystyle 3\cdot 4^{3}}$ . Its dual is deltoidal icositetrahedron, a Catalan solid, shares the same symmetry as the rhombicuboctahedron.^[15]

The elongated square gyrobicupola is the only polyhedron resembling the rhombicuboctahedron. The difference is that the elongated square gyrobicupola is constructed by twisting one of its cupolae. It was once considered as the 14th Archimedean solid, until it was discovered that it is not vertex-transitive, categorizing it as the Johnson solid instead.^[16]

The skeleton of a rhombicuboctahedron can be described as a graph. It is polyhedral graph, meaning that it is planar and 3-vertex-connected. In other words, the edges of a graph are not crossed while being drawn, and removing any two of its vertices leaves a connected subgraph. It has 24 vertices and 48 edges. It is a quartic, meaning each of its vertices is connected by four vertices. This graph is classified as Archimedean graph, because it resembles the graph of Archimedean solid.^[17]

The rhombicuboctahedron appears in the architecture, with an example of the building being the National Library located at Minsk.^[18] The Wilson House is another example of the rhombicuboctahedron building, although its module was depicted as a truncated cube in which the edges are all cut off. It was built during the Second World War and Operation Breakthrough in the 1960s.^[19]

The rhombicuboctahedron may also be found in toys. For example, the lines along which a Rubik's Cube can be turned are, projected onto a sphere, similar, topologically identical, to a rhombicuboctahedron's edges. Variants using the Rubik's Cube mechanism have been produced, which closely resemble the rhombicuboctahedron. During the Rubik's Cube craze of the 1980s, at least two twisty puzzles sold had the form of a rhombicuboctahedron (the mechanism was similar to that of a Rubik's Cube)^[20][21] Another example may be found in dice from Corfe Castle, each of which square faces have marks of pairs of letters and pips.^[22]

The rhombicuboctahedron may also appear in art. An example is the 1495 Portrait of Luca Pacioli, traditionally attributed to Jacopo de' Barbari, which includes a glass rhombicuboctahedron half-filled with water, which may have been painted by Leonardo da Vinci.^[23] The first printed version of the rhombicuboctahedron was by Leonardo and appeared in Pacioli's Divina proportione (1509).

• Truncated rhombicuboctahedron
• Moravian star

• Weisstein, Eric W., "Rhombicuboctahedron" ("Archimedean solid") at MathWorld.
  • Weisstein, Eric W. "Small rhombicuboctahedral graph". MathWorld.
• Klitzing, Richard. "3D convex uniform polyhedra x3o4x - sirco".
• The Uniform Polyhedra
• Virtual Reality Polyhedra The Encyclopedia of Polyhedra
• Editable printable net of a rhombicuboctahedron with interactive 3D view
• Rhombicuboctahedron Star by Sándor Kabai, Wolfram Demonstrations Project.
• Rhombicuboctahedron: paper strips for plaiting