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All 4 Idaho votes to the Electoral College | ||||||||||||||||||||||||||
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The 1948 United States presidential election in Idaho took place on November 2, 1948, as part of the 1948 United States presidential election. Idaho voters chose four[2] representatives, or electors, to the Electoral College, who voted for President and Vice President.
Idaho was won by incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 49.98% of the popular vote, against Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 47.26% of the popular vote.[3][4] As of 2017, this is the last election in which Bonneville County, Bingham County, Madison County, Jefferson County, [and [Oneida County, Idaho|Oneida County]] voted for the Democratic candidate.
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Harry S. Truman (inc.) | 107,370 | 49.98% | |
| Republican | Thomas Dewey | 101,514 | 47.26% | |
| Progressive | Henry A. Wallace | 4,972 | 2.31% | |
| Prohibition | Claude A. Watson | 628 | 0.29% | |
| Socialist | Norman Thomas | 332 | 0.15% | |
| Total votes | 214,816 | 100% | ||
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