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A112653
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a(n) squared is congruent to a(n) (mod 13).
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4
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0, 1, 13, 14, 26, 27, 39, 40, 52, 53, 65, 66, 78, 79, 91, 92, 104, 105, 117, 118, 130, 131, 143, 144, 156, 157, 169, 170, 182, 183, 195, 196, 208, 209, 221, 222, 234, 235, 247, 248, 260, 261, 273, 274, 286, 287, 299, 300, 312, 313, 325, 326, 338, 339, 351
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OFFSET
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0,3
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COMMENTS
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LINKS
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FORMULA
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a(n) = (11*(-1+(-1)^n)+26*n)/4.
a(n) = a(n-1) + a(n-2) - a(n-3) for n > 2.
G.f.: x*(1+12*x) / ((1-x)^2*(1+x)). (End)
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EXAMPLE
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a(3) = 14 because 14*14 = 196 = 1 (mod 13) and 14 = 1 (mod 13).
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MAPLE
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m:= 13; for n from 0 to 300 do if n^2 mod m = n mod m then print(n) fi od;
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MATHEMATICA
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Select[Range[0, 400], MemberQ[{0, 1}, Mod[#, 13]]&] (* Vincenzo Librandi, May 17 2012 *)
Select[Range[0, 400], Mod[#, 13]==PowerMod[#, 2, 13]&] (* or *) LinearRecurrence[ {1, 1, -1}, {0, 1, 13}, 60] (* Harvey P. Dale, Feb 07 2023 *)
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PROG
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(Magma) I:=[0, 1, 13]; [n le 3 select I[n] else Self(n-1)+Self(n-2)-Self(n-3): n in [1..70]]; // Vincenzo Librandi, May 17 2012
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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STATUS
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approved
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