Loop inversion

  int i, a[100];
  i = 0;
  while (i < 100) {
    a[i] = 0;
    i++;
  }

is equivalent to:

  int i, a[100];
  i = 0;
  if (i < 100) {
    do {
      a[i] = 0;
      i++;
    } while (i < 100);
  }

Despite the seemingly greater complexity of the second example, it may actually run faster on modern CPUs because they use an instruction pipeline. By nature, any jump in the code causes a pipeline stall, which is a detriment to performance.

Additionally, loop inversion allows safe loop-invariant code motion.

      i := 0
 L1:  if i >= 100 goto L2
      a[i] := 0
      i := i + 1
      goto L1
 L2:  

Ifi had been initialized at 100, the instructions executed at runtime would have been:

  if i >= 100
  goto L2

Let us assume that i had been initialized to some value less than 100. Now let us look at the instructions executed at the moment after i has been incremented to 99 in the loop:

  goto L1
  if i < 100
  a[i] := 0
  i := i + 1
  goto L1
  if i >= 100
  goto L2
  <<at L2>>

Now, let's look at the optimized version:

      i := 0
      if i >= 100 goto L2
 L1:  a[i] := 0
      i := i + 1
      if i < 100 goto L1
 L2:

Again, let's look at the instructions executed if i is initialized to 100:

  if i >= 100
  goto L2

We didn't waste any cycles compared to the original version. Now consider the case where i has been incremented to 99:

  if i < 100
  goto L1
  a[i] := 0
  i := i + 1
  if i < 100
  <<at L2>>

As you can see, two gotos (and thus, two pipeline stalls) have been eliminated in the execution.