Solar zenith angle

$${\displaystyle \cos \theta _{s}=\sin \alpha _{s}=\sin \Phi \sin \delta +\cos \Phi \cos \delta \cos h}$$ 

where

• ${\displaystyle \theta _{s}}$  is the solar zenith angle
• ${\displaystyle \alpha _{s}}$  is the solar altitude angle, ${\displaystyle \alpha _{s}=90^{\circ }-\theta _{s}}$ 
• ${\displaystyle h}$  is the hour angle, in the local solar time.
• ${\displaystyle \delta }$  is the current declination of the Sun
• ${\displaystyle \Phi }$  is the local latitude.

While the formula can be derived by applying the cosine law to the zenith-pole-Sun spherical triangle, the spherical trigonometry is a relatively esoteric subject.

By introducing the coordinates of the subsolar point and using vector analysis, the formula can be obtained straightforward without incurring the use of spherical trigonometry.^[4]

In the Earth-Centered Earth-Fixed (ECEF) geocentric Cartesian coordinate system, let ${\displaystyle (\phi _{s},\lambda _{s})}$  and ${\displaystyle (\phi _{o},\lambda _{o})}$  be the latitudes and longitudes, or coordinates, of the subsolar point and the observer's point, then the upward-pointing unit vectors at the two points, ${\displaystyle \mathbf {S} }$  and ${\displaystyle \mathbf {V} _{oz}}$ , are

$${\displaystyle \mathbf {S} =\cos \phi _{s}\cos \lambda _{s}{\mathbf {i} }+\cos \phi _{s}\sin \lambda _{s}{\mathbf {j} }+\sin \phi _{s}{\mathbf {k} },}$$  $${\displaystyle \mathbf {V} _{oz}=\cos \phi _{o}\cos \lambda _{o}{\mathbf {i} }+\cos \phi _{o}\sin \lambda _{o}{\mathbf {j} }+\sin \phi _{o}{\mathbf {k} }.}$$ 

where ${\displaystyle {\mathbf {i} }}$ , ${\displaystyle {\mathbf {j} }}$  and ${\displaystyle {\mathbf {k} }}$  are the basis vectors in the ECEF coordinate system.

Now the cosine of the solar zenith angle, ${\displaystyle \theta _{s}}$ , is simply the dot product of the above two vectors

$${\displaystyle \cos \theta _{s}=\mathbf {S} \cdot \mathbf {V} _{oz}=\sin \phi _{o}\sin \phi _{s}+\cos \phi _{o}\cos \phi _{s}\cos(\lambda _{s}-\lambda _{o}).}$$ 

Note that ${\displaystyle \phi _{s}}$  is the same as ${\displaystyle \delta }$ , the declination of the Sun, and ${\displaystyle \lambda _{s}-\lambda _{o}}$  is equivalent to ${\displaystyle -h}$ , where ${\displaystyle h}$  is the hour angle defined earlier. So the above format is mathematically identical to the one given earlier.

Additionally, Ref. ^[4] also derived the formula for solar azimuth angle in a similar fashion without using spherical trigonometry.

At any given location on any given day, the solar zenith angle, ${\displaystyle \theta _{s}}$ , reaches its minimum, ${\displaystyle \theta _{\text{min}}}$ , at local solar noon when the hour angle ${\displaystyle h=0}$ , or ${\displaystyle \lambda _{s}-\lambda _{o}=0}$ , namely, ${\displaystyle \cos \theta _{\text{min}}=\cos(|\phi _{o}-\phi _{s}|)}$ , or ${\displaystyle \theta _{\text{min}}=|\phi _{o}-\phi _{s}|}$ . If ${\displaystyle \theta _{\text{min}}>90^{\circ }}$ , it is polar night.

And at any given location on any given day, the solar zenith angle, ${\displaystyle \theta _{s}}$ , reaches its maximum, ${\displaystyle \theta _{\text{max}}}$ , at local midnight when the hour angle ${\displaystyle h=-180^{\circ }}$ , or ${\displaystyle \lambda _{s}-\lambda _{o}=-180^{\circ }}$ , namely, ${\displaystyle \cos \theta _{\text{max}}=\cos(180^{\circ }-|\phi _{o}+\phi _{s}|)}$ , or ${\displaystyle \theta _{\text{max}}=180^{\circ }-|\phi _{o}+\phi _{s}|}$ . If ${\displaystyle \theta _{\text{max}}<90^{\circ }}$ , it is polar day.

The calculated values are approximations due to the distinction between common/geodetic latitude and geocentric latitude. However, the two values differ by less than 12 minutes of arc, which is less than the apparent angular radius of the sun.

The formula also neglects the effect of atmospheric refraction.^[5]

Sunset and sunrise occur (approximately) when the zenith angle is 90°, where the hour angle h₀ satisfies^[2] $${\displaystyle \cos h_{0}=-\tan \Phi \tan \delta .}$$ 

Precise times of sunset and sunrise occur when the upper limb of the Sun appears, as refracted by the atmosphere, to be on the horizon.

A weighted daily average zenith angle, used in computing the local albedo of the Earth, is given by $${\displaystyle {\overline {\cos \theta _{s}}}={\frac {\displaystyle \int _{-h_{0}}^{h_{0}}Q\cos \theta _{s}\,{\text{d}}h}{\displaystyle \int _{-h_{0}}^{h_{0}}Q\,{\text{d}}h}}}$$  where Q is the instantaneous irradiance.^[2]

For example, the solar elevation angle is :

• 90° if you are on the equator, a day of equinox, at a solar hour of twelve
• near 0° at the sunset or at the sunrise
• between −90° and 0° during the night (midnight)

An exact calculation is given in position of the Sun. Other approximations exist elsewhere.^[6]

• Azimuth
• Solar azimuth angle
• Horizontal coordinate system
• List of orbits
• Photovoltaic mounting system § Orientation and inclination
• Position of the Sun
• Sun path
• Sunrise
• Sunset
• Sun transit time