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1828 United States presidential election in Alabama






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From Wikipedia, the free encyclopedia
 


1828 United States presidential election in Alabama

← 1824 October 31 – December 2, 1828 1832 →
 
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 5 0
Popular vote 16,736 1,878
Percentage 89.89% 10.09%

County Results

President before election

John Quincy Adams
Democratic-Republican

Elected President

Andrew Jackson
Democratic

The 1828 United States presidential election in Alabama took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose five representatives, or electors, to the Electoral College, who voted for President and Vice President.

Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Alabama by a margin of 79.80%.

Results[edit]

1828 United States presidential election in Alabama[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 16,736 89.89% 5
National Republican John Quincy Adams (incumbent) 1,878 10.09% 0
N/A Other 4 0.02% 0
Totals 18,618 100.00% 5

See also[edit]

References[edit]

  1. ^ "1828 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved February 28, 2013.

Retrieved from "https://en.wikipedia.org/w/index.php?title=1828_United_States_presidential_election_in_Alabama&oldid=1230526968"

Categories: 
1828 United States presidential election by state
United States presidential elections in Alabama
1828 Alabama elections
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This page was last edited on 23 June 2024, at 07:09 (UTC).

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