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1832 United States presidential election in Rhode Island
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From Wikipedia, the free encyclopedia
1832 United States presidential election in Rhode Island|
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|
County Results
Clay
40-50%
50-60%
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Jackson
50-60%
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The 1832 United States presidential election in Rhode Island took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
Rhode Island voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Rhode Island by a margin of 13.86%.
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Retrieved from "https://en.wikipedia.org/w/index.php?title=1832_United_States_presidential_election_in_Rhode_Island&oldid=1220930140"
Categories:
●1832 United States presidential election by state
●United States presidential elections in Rhode Island
●1832 Rhode Island elections
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