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The 1840 United States presidential election in New Hampshire took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.
New Hampshire voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won New Hampshire by a margin of 10.78%.
1840 United States presidential election in New Hampshire[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Martin Van BurenofNew York | Richard M. JohnsonofKentucky | 32,774 | 54.66% | 7 | 100.00% | ||
Whig | William Henry HarrisonofOhio | John TylerofVirginia | 26,310 | 43.88% | 0 | 0.00% | ||
Liberty | James G. BirneyofNew York | Thomas EarleofPennsylvania | 872 | 1.45% | 0 | 0.00% | ||
Total | 59,956 | 100.00% | 7 | 100.00% |
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Presidential elections |
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Senate elections |
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House elections |
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Gubernatorial elections |
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Legislative elections |
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State and district results of the 1840 United States presidential election
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