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1 General election  



1.1  Results  







2 References  














1849 Maine gubernatorial election







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From Wikipedia, the free encyclopedia
 


1849 Maine gubernatorial election

← 1848 10 September 1849 1850 →
 
Nominee John Hubbard Elijah Hamlin George F. Talbot
Party Democratic Whig Free Soil
Popular vote 37,636 28,056 7,987
Percentage 51.01% 38.03% 10.83%

Governor before election

John W. Dana
Democratic

Elected Governor

John Hubbard
Democratic

The 1849 Maine gubernatorial election was held on 10 September 1849 in order to elect the Governor of Maine. Democratic nominee and former member of the Maine Senate John Hubbard defeated Whig nominee and former member of the Maine House of Representatives Elijah Hamlin and Free Soil Party nominee George F. Talbot.[1]

General election[edit]

On election day, 10 September 1849, Democratic nominee John Hubbard won the election by a margin of 9,580 votes against his foremost opponent Whig nominee Elijah Hamlin, thereby retaining Democratic control over the office of governor. Hubbard was sworn in as the 22nd governor of Maine on 8 May 1850.[2]

Results[edit]

Maine gubernatorial election, 1849
Party Candidate Votes %
Democratic John Hubbard 37,636 51.01
Whig Elijah Hamlin 28,056 38.03
Free Soil George F. Talbot 7,987 10.83
Scattering 102 0.13
Total votes 73,781 100.00
Democratic hold

References[edit]

  1. ^ "Gov. John Hubbard". nga.org. Retrieved 16 April 2024.
  • ^ "ME Governor". ourcampaigns.com. 21 April 2005. Retrieved 16 April 2024.

  • Retrieved from "https://en.wikipedia.org/w/index.php?title=1849_Maine_gubernatorial_election&oldid=1219261215"

    Categories: 
    Maine gubernatorial elections
    1849 United States gubernatorial elections
    September 1849 events
    1849 in Maine
    1840s in Maine
    1840s Maine elections
    1849 elections
    1849 elections in North America
    1849 elections in the United States
    United States gubernatorial elections in the 1840s
    Government of Maine
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