Contents

1968 United States presidential election in Rhode Island

1968 United States presidential election in Rhode Island

← 1964 November 5, 1968[1] 1972 →

Nominee Hubert Humphrey Richard Nixon Party Democratic Republican Home state Minnesota New York[a] Running mate Edmund Muskie Spiro Agnew Electoral vote 4 0 Popular vote 246,518 122,359 Percentage 64.03% 31.78%

County Results Municipality Results Humphrey   40-50%   50-60%   60-70%   70-80% Nixon   40-50%   50-60%   60-70%

President before election Lyndon B. Johnson Democratic Elected President Richard Nixon Republican

Elections in Rhode Island
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Ballot measures 2020 Question 1
Providence Mayoral elections 1998 2002 2006 2010 2014 2018 2022
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The 1968 United States presidential election in Rhode Island took place on November 5, 1968, as part of the 1968 United States presidential election. Voters chose four^[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Rhode Island was won by the Democratic candidate, Vice President Hubert Humphrey, with 64.03% of the popular vote, against the Republican candidate, former Senator and Vice President Richard Nixon, with 31.78% of the popular vote. American Independent Party candidate George Wallace also appeared on the ballot, finishing with 4.07% of the popular vote.^[3][4] Despite the state trending 30 points Republican after setting a record in 1964, the state continued to overwhelmingly vote for the Democratic candidate.

Nixon was the first Republican to win the presidency without gaining the majority vote in Washington, Kent, and Newport counties.

Results[edit]

By county[edit]

See also[edit]

• United States presidential elections in Rhode Island

Notes[edit]

References[edit]

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