Anelimination reaction is a type of organic reaction in which two substituents are removed from a molecule in either a one- or two-step mechanism.[2] The one-step mechanism is known as the E2 reaction, and the two-step mechanism is known as the E1 reaction. The numbers refer not to the number of steps in the mechanism, but rather to the kinetics of the reaction: E2 is bimolecular (second-order) while E1 is unimolecular (first-order). In cases where the molecule is able to stabilize an anion but possesses a poor leaving group, a third type of reaction, E1CB, exists. Finally, the pyrolysisofxanthate and acetateesters proceed through an "internal" elimination mechanism, the Ei mechanism.
The E2 mechanism, where E2 stands for bimolecular elimination, involves a one-step mechanism in which carbon-hydrogen and carbon-halogen bonds break to form a double bond (C=C Pi bond).
The specifics of the reaction are as follows:
E2 is a single step elimination, with a single transition state.
It is typically undergone by primary substituted alkyl halides, but is possible with some secondary alkyl halides and other compounds.
The reaction rateissecond order, because it's influenced by both the alkyl halide and the base (bimolecular).
Because the E2 mechanism results in the formation of a pi bond, the two leaving groups (often a hydrogen and a halogen) need to be antiperiplanar. An antiperiplanar transition state has staggered conformation with lower energy than a synperiplanar transition state which is in eclipsed conformation with higher energy. The reaction mechanism involving staggered conformation is more favorable for E2 reactions (unlike E1 reactions).
E2 typically uses a strong base. It must be strong enough to remove a weakly acidic hydrogen.
In order for the pi bond to be created, the hybridization of carbons needs to be lowered from sp3tosp2.
E1 is a model to explain a particular type of chemical elimination reaction. E1 stands for unimolecular elimination and has the following specifications
It is a two-step process of elimination: ionization and deprotonation.
E1 typically takes place with tertiary alkyl halides, but is possible with some secondary alkyl halides.
The reaction rate is influenced only by the concentration of the alkyl halide because carbocation formation is the slowest step, as known as the rate-determining step. Therefore, first-order kinetics apply (unimolecular).
The reaction usually occurs in the complete absence of a base or the presence of only a weak base (acidic conditions and high temperature).
E1 reactions are in competition with SN1 reactions because they share a common carbocationic intermediate.
An example in scheme 2 is the reaction of tert-butylbromide with potassium ethoxide in ethanol.
E1 eliminations happen with highly substituted alkyl halides for two main reasons.
Highly substituted alkyl halides are bulky, limiting the room for the E2 one-step mechanism; therefore, the two-step E1 mechanism is favored.
Highly substituted carbocations are more stable than methyl or primary substituted cations. Such stability gives time for the two-step E1 mechanism to occur.
If SN1 and E1 pathways are competing, the E1 pathway can be favored by increasing the heat.
The reaction rate is influenced by the reactivity of halogens, iodide and bromide being favored. Fluoride is not a good leaving group, so eliminations with fluoride as the leaving group have slower rates than other halogens .
There is a certain level of competition between the elimination reaction and nucleophilic substitution. More precisely, there are competitions between E2 and SN2 and also between E1 and SN1. Generally, elimination is favored over substitution when
For example, when a 3° haloalkane is reacts with an alkoxide, due to strong basic character of the alkoxide and unreactivity of 3° group towards SN2, only alkene formation by E2 elimination is observed. Thus, elimination by E2 limits the scope of the Williamson ether synthesis (an SN2 reaction) to essentially only 1° haloalkanes; 2° haloalkanes generally do not give synthetically useful yields, while 3° haloalkanes fail completely.
With strong base, 3° haloalkanes give elimination by E2. With weak bases, mixtures of elimination and substitution products form by competing SN1 and E1 pathways.
The case of 2° haloalkanes is relatively complex. For strongly basic nucleophiles (pKaH > 11, e.g., hydroxide, alkoxide, acetylide), the result is generally elimination by E2, while weaker bases that are still good nucleophiles (e.g., acetate, azide, cyanide, iodide) will give primarily SN2. Finally, weakly nucleophilic species (e.g., water, alcohols, carboxylic acids) will give a mixture of SN1 and E1.
For 1° haloalkanes with β-branching, E2 elimination is still generally preferred over SN2 for strongly basic nucleophiles. Unhindered 1° haloalkanes favor SN2 when the nucleophile is also unhindered. However, strongly basic and hindered nucleophiles favor E2.
In general, with the exception of reactions in which E2 is impossible because β hydrogens are unavailable (e.g. methyl, allyl, and benzyl halides),[4] clean SN2 substitution is hard to achieve when strong bases are used, as alkene products arising from elimination are almost always observed to some degree. On the other hand, clean E2 can be achieved by simply selecting a sterically hindered base (e.g., potassium tert-butoxide). Similarly, attempts to effect substitution by SN1 almost always result in a product mixture contaminated by some E1 product (again, with the exception of cases where the lack of β hydrogens makes elimination impossible).[5]
In one study[6] the kinetic isotope effect (KIE) was determined for the gas phase reaction of several alkyl halides with the chlorate ion. In accordance with an E2 elimination the reaction with t-butyl chloride results in a KIE of 2.3. The methyl chloride reaction (only SN2 possible) on the other hand has a KIE of 0.85 consistent with a SN2 reaction because in this reaction type the C-H bonds tighten in the transition state. The KIE's for the ethyl (0.99) and isopropyl (1.72) analogues suggest competition between the two reaction modes.
Elimination reactions other than β-elimination[edit]
β-Elimination, with loss of electrofuge and nucleofuge on vicinal carbon atoms, is by far the most common type of elimination. The ability to form a stable product containing a C=C or C=X bond, as well as orbital alignment considerations, strongly favors β-elimination over other elimination processes.[7] However, other types are known, generally for systems where β-elimination cannot occur.
The next most common type of elimination reaction is α-elimination. For a carbon center, the result of α-elimination is the formation of a carbene, which includes "stable carbenes" such as carbon monoxideorisocyanides. For instance, α-elimination the elements of HCl from chloroform (CHCl3) in the presence of strong base is a classic approach for the generation of dichlorocarbene, :CCl2, as a reactive intermediate. On the other hand, formic acid undergoes α-elimination to afford the stable products water and carbon monoxide under acidic conditions. α-Elimination may also occur on a metal center, one particularly common result of which is lowering of both the metal oxidation state and coordination number by 2 units in a process known as reductive elimination. (Confusingly, in organometallic terminology, the terms α-elimination and α-abstraction refer to processes that result in formation of a metal-carbene complex.[8] In these reactions, it is the carbon adjacent to the metal that undergoes α-elimination.)
In certain special cases, γ- and higher eliminations to form three-membered or larger rings is also possible in both organic and organometallic processes. For instance, certain Pt(II) complexes undergo γ- and δ-elimination to give metallocycles.[9] More recently, γ-silyl elimination of a silylcyclobutyl tosylate has been used to prepare strained bicyclic systems.[10]
^In rare cases in which β hydrogens are unavailable but substitution is disfavored, α-elimination to form a carbene can sometimes occur. In particular: (1) Trihalomethanes like chloroform can react with NaOH to form dihalocarbenes (substitution is electronically disfavored). (2) Allyl and benzyl chloride can react with lithium tetramethylpiperide (LiTMP) to form vinylcarbene and phenylcarbene, respectively (substitution is sterically disfavored).
^Carey, Francis A. (2003). Organic Chemistry (5th ed.). New York: McGraw-Hill. p. 350. ISBN0-07-242458-3.
^Stephanie M. Villano; Shuji Kato; Veronica M. Bierbaum (2006). "Deuterium Kinetic Isotope Effects in Gas-Phase SN2 and E2 Reactions: Comparison of Experiment and Theory". J. Am. Chem. Soc.128 (3): 736–737. doi:10.1021/ja057491d. PMID16417360.
^Anslyn, Eric V. (2006). Modern physical organic chemistry. Dougherty, Dennis A., 1952-. Sausalito, CA: University Science. ISBN1891389319. OCLC55600610.
^Crabtree, Robert H. (2009). The organometallic chemistry of the transition metals (5th ed.). Hoboken, N.J.: Wiley. ISBN9780470257623. OCLC268790870.
^Moore, Stephen S.; DiCosimo, Robert; Sowinski, Allan F.; Whitesides, George M. (1981-02-01). "Ring strain in bis(triethylphosphine)-3,3-dimethylplatinacyclobutane is small". Journal of the American Chemical Society. 103 (4): 948–949. doi:10.1021/ja00394a043. ISSN0002-7863.
^Kelly, Christopher B.; Colthart, Allison M.; Constant, Brad D.; Corning, Sean R.; Dubois, Lily N. E.; Genovese, Jacqueline T.; Radziewicz, Julie L.; Sletten, Ellen M.; Whitaker, Katherine R. (2011-04-01). "Enabling the Synthesis of Perfluoroalkyl Bicyclobutanes via 1,3 γ-Silyl Elimination". Organic Letters. 13 (7): 1646–1649. doi:10.1021/ol200121f. ISSN1523-7060. PMID21366262.
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