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Lexicographic order topology on the unit square

The lexicographical ordering gives a total ordering ${\displaystyle \prec }$ on the points in the unit square: if (x,y) and (u,v) are two points in the square, (x,y) ${\displaystyle \scriptstyle \prec }$ (u,v) if and only if either x < uorboth x = u and y < v. Stated symbolically, $${\displaystyle (x,y)\prec (u,v)\iff (x<$$u)\lor (x=u\land y<v)}

The lexicographic order topology on the unit square is the order topology induced by this ordering.

Properties[edit]

The order topology makes S into a completely normal Hausdorff space.^[3] Since the lexicographical order on S can be proven to be complete, this topology makes S into a compact space. At the same time, S contains an uncountable number of pairwise disjoint open intervals, each homeomorphic to the real line, for example the intervals ${\displaystyle U_{x}=\{(x,y):1/4<y<1/2\}}$ for ${\displaystyle 0\leq x\leq 1}$. So S is not separable, since any dense subset has to contain at least one point in each ${\displaystyle U_{x}}$. Hence S is not metrizable (since any compact metric space is separable); however, it is first countable. Also, S is connected and locally connected, but not path connected and not locally path connected.^[1] Its fundamental group is trivial.^[2]

See also[edit]

• List of topologies
• Long line

Notes[edit]

References[edit]

• Steen, L. A.; Seebach, J. A. (1995), Counterexamples in Topology, Dover, ISBN 0-486-68735-X