Osborne Hill | |
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Location of Osborne Hill within New York Show map of New YorkOsborne Hill (the United States) Show map of the United States | |
Highest point | |
Elevation | 1,299 feet (396 m) |
Coordinates | 43°05′12″N 75°01′52″W / 43.08667°N 75.03111°W / 43.08667; -75.03111[1] |
Geography | |
Location | NW of Herkimer, New York, U.S. |
Topo map | USGS Ilion |
Osborne Hill is a summitinCentral New York RegionofNew York in the town of HerkimerinHerkimer County, northwest of the village of Herkimer.
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