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1 External links  





2 Notes  














Rosedale, Austin, Texas







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Coordinates: 30°1846N 97°4438W / 30.3127°N 97.7438°W / 30.3127; -97.7438
 

From Wikipedia, the free encyclopedia
 


Map
Neighborhood map

The Rosedale neighborhood is located in north central Austin, Texas. The neighborhood is bordered by on 38th Street to the south, Shoal Creek to the west, North Loop / Hancock Drive to the north, and Lamar Boulevard to the east

Ramsey Park is located in the middle of the neighborhood, and has a swimming pool, tennis courts, a baseball diamond, a basketball court, playgrounds, and picnic areas.[1] There are over 1200 homes in the area, a variety of businesses within walking distance, and a network of medical services close by, most notably Seton Hospital.[2]

Rosedale was first developed as farm and dairy land in the 1860s. In the 1900s, four florists and nurseries were based in the area; much of the nursery stock planted during that time remains.[3]

Many of the homes in the Rosedale area were built during the 1930s and 1940s; since then, many have been added onto and many new homes have been built.[citation needed]

[edit]

map

Notes

[edit]
  1. ^ "Parks, trails, and open space in Austin and Travis County | Austin Parks Foundation". Austinparks.org. Archived from the original on 2012-03-21. Retrieved 2015-10-31.
  • ^ "Medical Center Austin". Seton. Retrieved 2015-10-31.
  • ^ "Rosedale history - Rosedale Neighborhood". Rosedaleaustin.org. Retrieved 2015-10-31.
  • 30°18′46N 97°44′38W / 30.3127°N 97.7438°W / 30.3127; -97.7438


    Retrieved from "https://en.wikipedia.org/w/index.php?title=Rosedale,_Austin,_Texas&oldid=1155694107"

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    This page was last edited on 19 May 2023, at 08:53 (UTC).

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