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For a long time i couldn't understand step 2 to step 3 until i realised M'(x)=a(x)M(x). Prehaps this is the key fact.
Also the in the example it isn't clear how you got to m(x)=1/x^2 from the previous step.
Some people may not be used to function notation and may prefer to use dy/dx etc. etc. (ie. me) Would it be a good idea to change the page to include both notations.(Lahoski (talk) 11:06, 11 March 2008 (UTC))[reply]
(Note we do not need to include the integrating constant - we need only a solution, not the general solution)[edit]
This comment in the first example misses the point. Even if you add in the integrating constant, it would only cancel out at the end when you have . Hence, changing M(x) in this fashion has no effect on the final solution.
Rwilsker (talk) 17:18, 25 May 2008 (UTC)[reply]
As stated in the introduction: "... multiplying through by an integrating factor allows an inexact differential to be made into an exact differential...".
However, there is not explained if this is always possible and, if yes, why?
The page of "inexact differential" gives a well known example of an integrating factor and nothing more.
The use of this term in the article is inconsistent with the usual definition of a partial derivative. I can't tell how the expression before multiplying by M(x) is the partial derivative of the same expression that the total derivative is of. I would suggest removing this use of this term unless it can be made clear how exactly it is a partial derivative.--Jasper Deng(talk)14:46, 17 August 2014 (UTC)[reply]
No inline citations, only one source and the source does not support the bulk of the information on the page. Most of the page is poorly formatted, both the way the equations are integrated into the article and the overall article layout.