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Contents

   



(Top)
 


1 Theorem  



1.1  Proofs  



1.1.1  Fourier series  





1.1.2  Integration by parts  





1.1.3  Functional analysis  









2 Spectral geometry  





3 Application to the isoperimetric inequality  





4 References  














Wirtinger's inequality for functions






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From Wikipedia, the free encyclopedia
 


For other inequalities named after Wirtinger, see Wirtinger's inequality.

In the mathematical field of analysis, the Wirtinger inequality is an important inequality for functions of a single variable, named after Wilhelm Wirtinger. It was used by Adolf Hurwitz in 1901 to give a new proof of the isoperimetric inequality for curves in the plane. A variety of closely related results are today known as Wirtinger's inequality, all of which can be viewed as certain forms of the Poincaré inequality.

Theorem[edit]

There are several inequivalent versions of the Wirtinger inequality:

and equality holds if and only if y(x) = c sin 2π(x − α)/L for some numbers c and α.[1]
and equality holds if and only if y(x) = c sin πx/L for some number c.[1]
and equality holds if and only if y(x) = c cos πx/L for some number c.[2]

Despite their differences, these are closely related to one another, as can be seen from the account given below in terms of spectral geometry. They can also all be regarded as special cases of various forms of the Poincaré inequality, with the optimal Poincaré constant identified explicitly. The middle version is also a special case of the Friedrichs inequality, again with the optimal constant identified.

Proofs[edit]

The three versions of the Wirtinger inequality can all be proved by various means. This is illustrated in the following by a different kind of proof for each of the three Wirtinger inequalities given above. In each case, by a linear change of variables in the integrals involved, there is no loss of generality in only proving the theorem for one particular choice of L.

Fourier series[edit]

Consider the first Wirtinger inequality given above. Take L to be . Since Dirichlet's conditions are met, we can write

and the fact that the average value of y is zero means that a0 = 0. By Parseval's identity,

and

and since the summands are all nonnegative, the Wirtinger inequality is proved. Furthermore it is seen that equality holds if and only if an = bn = 0 for all n ≥ 2, which is to say that y(x) = a1 sin x + b1 cos x. This is equivalent to the stated condition by use of the trigonometric addition formulas.

Integration by parts[edit]

Consider the second Wirtinger inequality given above.[1] Take L to be π. Any differentiable function y(x) satisfies the identity

Integration using the fundamental theorem of calculus and the boundary conditions y(0) = y(π) = 0 then shows

This proves the Wirtinger inequality, since the second integral is clearly nonnegative. Furthermore, equality in the Wirtinger inequality is seen to be equivalent to y′(x) = y(x) cot x, the general solution of which (as computed by separation of variables) is y(x) = c sin x for an arbitrary number c.

There is a subtlety in the above application of the fundamental theorem of calculus, since it is not the case that y(x)2 cot x extends continuously to x = 0 and x = π for every function y(x). This is resolved as follows. It follows from the Hölder inequality and y(0) = 0 that

which shows that as long as

is finite, the limit of 1/x y(x)2asx converges to zero is zero. Since cot x < 1/x for small positive values of x, it follows from the squeeze theorem that y(x)2 cot x converges to zero as x converges to zero. In exactly the same way, it can be proved that y(x)2 cot x converges to zero as x converges to π.

Functional analysis[edit]

Consider the third Wirtinger inequality given above. Take L to be 1. Given a continuous function fon[0, 1] of average value zero, let Tf) denote the function uon[0, 1] which is of average value zero, and with u′′ + f = 0 and u′(0) = u′(1) = 0. From basic analysis of ordinary differential equations with constant coefficients, the eigenvalues of T are (kπ)−2 for nonzero integers k, the largest of which is then π−2. Because T is a bounded and self-adjoint operator, it follows that

for all f of average value zero, where the equality is due to integration by parts. Finally, for any continuously differentiable function yon[0, 1] of average value zero, let gn be a sequence of compactly supported continuously differentiable functions on (0, 1) which converge in L2toy. Then define

Then each yn has average value zero with yn′(0) = yn′(1) = 0, which in turn implies that yn′′ has average value zero. So application of the above inequality to f = −yn′′ is legitimate and shows that

It is possible to replace ynbyy, and thereby prove the Wirtinger inequality, as soon as it is verified that yn converges in L2toy. This is verified in a standard way, by writing

and applying the Hölder or Jensen inequalities.

This proves the Wirtinger inequality. In the case that y(x) is a function for which equality in the Wirtinger inequality holds, then a standard argument in the calculus of variations says that y must be a weak solution of the Euler–Lagrange equation y′′(x) + y(x) = 0 with y′(0) = y′(1) = 0, and the regularity theory of such equations, followed by the usual analysis of ordinary differential equations with constant coefficients, shows that y(x) = c cos πx for some number c.

To make this argument fully formal and precise, it is necessary to be more careful about the function spaces in question.[2]

Spectral geometry[edit]

In the language of spectral geometry, the three versions of the Wirtinger inequality above can be rephrased as theorems about the first eigenvalue and corresponding eigenfunctions of the Laplace–Beltrami operator on various one-dimensional Riemannian manifolds:[3]

These can also be extended to statements about higher-dimensional spaces. For example, the Riemannian circle may be viewed as the one-dimensional version of either a sphere, real projective space, or torus (of arbitrary dimension). The Wirtinger inequality, in the first version given here, can then be seen as the n = 1 case of any of the following:

The second and third versions of the Wirtinger inequality can be extended to statements about first Dirichlet and Neumann eigenvalues of the Laplace−Beltrami operator on metric ballsinEuclidean space:

Application to the isoperimetric inequality[edit]

In the first form given above, the Wirtinger inequality can be used to prove the isoperimetric inequality for curves in the plane, as found by Adolf Hurwitz in 1901.[8] Let (x, y) be a differentiable embedding of the circle in the plane. Parametrizing the circle by [0, 2π] so that (x, y) has constant speed, the length L of the curve is given by

and the area A enclosed by the curve is given (due to Stokes theorem) by

Since the integrand of the integral defining L is assumed constant, there is

which can be rewritten as

The first integral is clearly nonnegative. Without changing the area or length of the curve, (x, y) can be replaced by (x, y + z) for some number z, so as to make y have average value zero. Then the Wirtinger inequality can be applied to see that the second integral is also nonnegative, and therefore

which is the isoperimetric inequality. Furthermore, equality in the isoperimetric inequality implies both equality in the Wirtinger inequality and also the equality x′(t) + y(t) = 0, which amounts to y(t) = c1 sin(t – α) and then x(t) = c1 cos(t – α) + c2 for arbitrary numbers c1 and c2. These equations mean that the image of (x, y) is a round circle in the plane.

References[edit]

  • ^ a b Brezis 2011, pp. 511–513, 576–578.
  • ^ Chavel 1984, Sections I.3 and I.5.
  • ^ Stein & Weiss 1971, Chapter IV.2.
  • ^ Chavel 1984, p. 36.
  • ^ Chavel 1984, Section II.2.
  • ^ a b Chavel 1984, Theorem II.5.4.
  • ^ Hardy, Littlewood & Pólya 1952, Section 7.7; Hurwitz 1901.

  • Retrieved from "https://en.wikipedia.org/w/index.php?title=Wirtinger%27s_inequality_for_functions&oldid=1224026213"

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    This page was last edited on 15 May 2024, at 20:26 (UTC).

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