Yecuatla
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Municipality and town
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Location in Mexico | |
Coordinates: 19°52′N 96°47′W / 19.867°N 96.783°W / 19.867; -96.783 | |
Country | ![]() |
State | Veracruz |
Area | |
• Total | 135.72 km2 (52.40 sq mi) |
Population
(2005)
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• Total | 11,446 |
Time zone | UTC-6 (Central Standard Time) |
• Summer (DST) | UTC-5 (Central Daylight Time) |
Yecuatla is a municipality located in the north zone in the Mexican stateofVeracruz, about 40 km from the state capital Xalapa. It has a surface of 135.72 km2. It is located at 19°52′N 96°47′W / 19.867°N 96.783°W / 19.867; -96.783.
The name comes from the language Náhuatl, Yec-uauh-tlan; that means “Place of three snakes ".
The municipality of Yecuatla is bordered to the north-east by Colipa, to the south by Chiconquiaco, to the west by Misantla and to the north-west by Colipa.[1]
The climate in Yecuatla is warm-regular with an average temperature of 22.5°C, with rains in summer and autumn.
It produces principally maize, bean, green chile, orange fruit and coffee.
Every Augusts, a festival is held to celebrate Virgen de la Asunción, patron of the town and in December there is a festival held in honor of the Virgin of Guadalupe.
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