マイクロソフトは、同社のリレーショナルデータベースの時期メジャーアップ版となるSQL Server 2016がLinuxに対応することを公式に発表しました。 同社のエグゼクティブバイスプレジデントScott Guthrie氏は、Official Microsoft Blogのエントリ「Announcing SQL Server on Linux - The Official Microsoft Blog」で次のように書いています。 Today I’m excited to announce our plans to bring SQL Server to Linux as well. This will enable SQL Server to deliver a consistent data platform across Windows Server and Linux, as we
The document discusses testing the limits of MySQL by creating an extremely long SQL query with over 4,000 "UNION ALL" selections of the value "b". This exceeded the maximum length of SQL queries that MySQL servers can execute, which is defined by the max_allowed_packet system variable and has a maximum value of 1GB. Creating such a long meaningless query demonstrated that MySQL has limitations on
第二章 ナイーブツリー 「ブログのコメント欄をスレッド形式で見れるようにしたいよね・・・」 目的 階層構造を格納して、クエリを実行する こんなテーブル設計したとして、 comment_id parent_id comment etc
In Visual Studio 2022 17.10 Preview 2, we’ve introduced some UX updates and usability improvements to the Connection Manager. With these updates we provide a more seamless experience when connecting to remote systems and/or debugging failed connections. Please install the latest Preview to try it out. Read on to learn what the Connection ...
To run SQL code, press <kbd id=\"-lo996y_34\" data-key=\"Console.Execute.Multiline\">Ctrl+Enter</kbd></p>","<p id=\"-lo996y_35\">To cancel a running statement, press <kbd id=\"-lo996y_36\" data-key=\"Stop\">Ctrl+F2</kbd></p>"]}"> Enable the Database Tools and SQL plugin This functionality relies on the Database Tools and SQL plugin, which is bundled and enabled in RubyMine by default. If the relev
一週間悩んで、やっと分かったのでメモ。 こういうSQLの場合、前者よりも後者の方が速いです。 SELECT * FROM FooTable LEFT OUTER JOIN BarTable1 ON FooTable.ID = BarTable1.ID LEFT OUTER JOIN BarTable2 ON BarTable1.F_ID = BarTable2.ID LEFT OUTER JOIN BarTable3 ON BarTable2.F_ID = BarTable3.ID LEFT OUTER JOIN BarTable4 ON BarTable3.F_ID = BarTable4.ID LEFT OUTER JOIN BarTable5 ON BarTable4.F_ID = BarTable5.ID WHERE FooTable.Name = ? OR BarTable5.N
I have three tables/models. Recordings (id) has_many :hits has_many :tags, :through => :hits Hits (id, recording_id, tag_id) belongs_to :recordings belongs_to :tags Tags (id) has_many :hits has_many :recordings, :through => :hits I need to find all recordings that have all the tags that are passed in as a parameter. For example, find all recordings that have tag.id == 5, tag.id == 6, and tag.id ==
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