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Factorion

Let ${\displaystyle n}$ be a natural number. For a base ${\displaystyle b>1}$, we define the sum of the factorials of the digits^[5][6]of${\displaystyle n}$, ${\displaystyle \operatorname {SFD} _{b}:\mathbb {N} \rightarrow \mathbb {N} }$, to be the following:

${\displaystyle \operatorname {SFD} _{b}($n)=\sum _{i=0}^{k-1}d_{i}!.}

where ${\displaystyle k=\lfloor \log _{b}n\rfloor +1}$ is the number of digits in the number in base ${\displaystyle b}$, ${\displaystyle n!}$ is the factorialof${\displaystyle n}$ and

${\displaystyle d_{i}={\frac {n{\bmod {b^{i+1}}}-n{\bmod {b^{i}}}}{b^{i}}}}$

is the value of the ${\displaystyle i}$th digit of the number. A natural number ${\displaystyle n}$ is a ${\displaystyle b}$-factorion if it is a fixed point for ${\displaystyle \operatorname {SFD} _{b}}$, i.e. if ${\displaystyle \operatorname {SFD} _{b}($n)=n} .^[7] ${\displaystyle 1}$ and ${\displaystyle 2}$ are fixed points for all bases ${\displaystyle b}$, and thus are trivial factorions for all ${\displaystyle b}$, and all other factorions are nontrivial factorions.

For example, the number 145 in base ${\displaystyle b=10}$ is a factorion because ${\displaystyle 145=1!+4!+5!}$.

For ${\displaystyle b=2}$, the sum of the factorials of the digits is simply the number of digits ${\displaystyle k}$ in the base 2 representation since ${\displaystyle 0!=1!=1}$.

A natural number ${\displaystyle n}$ is a sociable factorion if it is a periodic point for ${\displaystyle \operatorname {SFD} _{b}}$, where ${\displaystyle \operatorname {SFD} _{b}^{k}($n)=n} for a positive integer ${\displaystyle k}$, and forms a cycle of period ${\displaystyle k}$. A factorion is a sociable factorion with ${\displaystyle k=1}$, and a amicable factorion is a sociable factorion with ${\displaystyle k=2}$.^[8][9]

All natural numbers ${\displaystyle n}$ are preperiodic points for ${\displaystyle \operatorname {SFD} _{b}}$, regardless of the base. This is because all natural numbers of base ${\displaystyle b}$ with ${\displaystyle k}$ digits satisfy ${\displaystyle b^{k-1}\leq n\leq (b-1)!($k)} . However, when ${\displaystyle k\geq b}$, then ${\displaystyle b^{k-1}>(b-1)!($k)} for ${\displaystyle b>2}$, so any ${\displaystyle n}$ will satisfy ${\displaystyle n>\operatorname {SFD} _{b}($n)} until ${\displaystyle n<b^{b}}$. There are finitely many natural numbers less than ${\displaystyle b^{b}}$, so the number is guaranteed to reach a periodic point or a fixed point less than ${\displaystyle b^{b}}$, making it a preperiodic point. For ${\displaystyle b=2}$, the number of digits ${\displaystyle k\leq n}$ for any number, once again, making it a preperiodic point. This means also that there are a finite number of factorions and cycles for any given base ${\displaystyle b}$.

The number of iterations ${\displaystyle i}$ needed for ${\displaystyle \operatorname {SFD} _{b}^{i}($n)} to reach a fixed point is the ${\displaystyle \operatorname {SFD} _{b}}$ function's persistenceof${\displaystyle n}$, and undefined if it never reaches a fixed point.

Factorions for SFD_b[edit]

b = (k − 1)![edit]

Let ${\displaystyle k}$ be a positive integer and the number base ${\displaystyle b=(k-1)!}$. Then:

• ${\displaystyle n_{1}=kb+1}$ is a factorion for ${\displaystyle \operatorname {SFD} _{b}}$ for all ${\displaystyle k.}$

${\displaystyle \operatorname {SFD} _{b}(n_{1})=d_{1}!+d_{0}!}$

${\displaystyle =k!+1!}$

${\displaystyle =k(k-1)!+1}$

${\displaystyle =d_{1}b+d_{0}}$

${\displaystyle =n_{1}}$

Thus ${\displaystyle n_{1}}$ is a factorion for ${\displaystyle F_{b}}$ for all ${\displaystyle k}$.

• ${\displaystyle n_{2}=kb+2}$ is a factorion for ${\displaystyle \operatorname {SFD} _{b}}$ for all ${\displaystyle k}$.

${\displaystyle \operatorname {SFD} _{b}(n_{2})=d_{1}!+d_{0}!}$

${\displaystyle =k!+2!}$

${\displaystyle =k(k-1)!+2}$

${\displaystyle =d_{1}b+d_{0}}$

${\displaystyle =n_{2}}$

Thus ${\displaystyle n_{2}}$ is a factorion for ${\displaystyle F_{b}}$ for all ${\displaystyle k}$.

Factorions

${\displaystyle k}$	${\displaystyle b}$	${\displaystyle n_{1}}$	${\displaystyle n_{2}}$
4	6	41	42
5	24	51	52
6	120	61	62
7	720	71	72

b = k! − k + 1[edit]

Let ${\displaystyle k}$ be a positive integer and the number base ${\displaystyle b=k!-k+1}$. Then:

• ${\displaystyle n_{1}=b+k}$ is a factorion for ${\displaystyle \operatorname {SFD} _{b}}$ for all ${\displaystyle k}$.

${\displaystyle \operatorname {SFD} _{b}(n_{1})=d_{1}!+d_{0}!}$

${\displaystyle =1!+k!}$

${\displaystyle =k!+1-k+k}$

${\displaystyle =1(k!-k+1)+k}$

${\displaystyle =d_{1}b+d_{0}}$

${\displaystyle =n_{1}}$

Thus ${\displaystyle n_{1}}$ is a factorion for ${\displaystyle F_{b}}$ for all ${\displaystyle k}$.

Factorions

${\displaystyle k}$	${\displaystyle b}$	${\displaystyle n_{1}}$
3	4	13
4	21	14
5	116	15
6	715	16

Table of factorions and cycles of SFD_b[edit]

All numbers are represented in base ${\displaystyle b}$.

Base ${\displaystyle b}$	Nontrivial factorion (${\displaystyle n\neq 1}$, ${\displaystyle n\neq 2}$)[10]	Cycles
2	${\displaystyle \varnothing }$	${\displaystyle \varnothing }$
3	${\displaystyle \varnothing }$	${\displaystyle \varnothing }$
4	13	3 → 12 → 3
5	144	${\displaystyle \varnothing }$
6	41, 42	${\displaystyle \varnothing }$
7	${\displaystyle \varnothing }$	36 → 2055 → 465 → 2343 → 53 → 240 → 36
8	${\displaystyle \varnothing }$	3 → 6 → 1320 → 12 175 → 12051 → 175
9	62558
10	145, 40585	871 → 45361 → 871[9] 872 → 45362 → 872[8]

See also[edit]

• Arithmetic dynamics
• Dudeney number
• Happy number
• Kaprekar's constant
• Kaprekar number
• Meertens number
• Narcissistic number
• Perfect digit-to-digit invariant
• Perfect digital invariant
• Sum-product number

References[edit]

External links[edit]

• Factorion at Wolfram MathWorld