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Latest revision Your text
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The stochastic process defined by

The stochastic process defined by

<math display="block"> X_t = \mu t + \sigma W_t</math>

<math display="block"> X_t = \mu t + \sigma W_t</math>

is called a '''Wiener process with drift μ''' and infinitesimal variance σ<sup>2</sup>. These processes exhaust continuous [[Lévy process]]es, which means that they are the only continuous Lévy processes,

is called a '''Wiener process with drift μ''' and infinitesimal variance σ<sup>2</sup>. These processes exhaust continuous [[Lévy process]]es.{{clarification needed|date=April 2021|reason=What is meant by "exhaust" here? Clearly not physical exhaustion. Is there an implicit claim of some theorem that any Levy process with continuous sample paths is a Wiener process with drift? If so, then there should be a citation for that theorem.}}

as a consequence of the Lévy–Khintchine representation.



Two random processes on the time interval [0, 1] appear, roughly speaking, when conditioning the Wiener process to vanish on both ends of [0,1]. With no further conditioning, the process takes both positive and negative values on [0, 1] and is called [[Brownian bridge]]. Conditioned also to stay positive on (0, 1), the process is called [[Brownian excursion]].<ref>{{cite journal |last=Vervaat |first=W. |year=1979 |title=A relation between Brownian bridge and Brownian excursion |journal=[[Annals of Probability]] |volume=7 |issue=1 |pages=143–149 |jstor=2242845 |doi=10.1214/aop/1176995155|doi-access=free }}</ref> In both cases a rigorous treatment involves a limiting procedure, since the formula ''P''(''A''|''B'') = ''P''(''A'' ∩ ''B'')/''P''(''B'') does not apply when ''P''(''B'') = 0.

Two random processes on the time interval [0, 1] appear, roughly speaking, when conditioning the Wiener process to vanish on both ends of [0,1]. With no further conditioning, the process takes both positive and negative values on [0, 1] and is called [[Brownian bridge]]. Conditioned also to stay positive on (0, 1), the process is called [[Brownian excursion]].<ref>{{cite journal |last=Vervaat |first=W. |year=1979 |title=A relation between Brownian bridge and Brownian excursion |journal=[[Annals of Probability]] |volume=7 |issue=1 |pages=143–149 |jstor=2242845 |doi=10.1214/aop/1176995155|doi-access=free }}</ref> In both cases a rigorous treatment involves a limiting procedure, since the formula ''P''(''A''|''B'') = ''P''(''A'' ∩ ''B'')/''P''(''B'') does not apply when ''P''(''B'') = 0.

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