Contents

Measure (mathematics)

This article includes a list of general references, but it lacks sufficient corresponding inline citations. Please help to improve this article by introducing more precise citations. (January 2021) (Learn how and when to remove this message)

Inmathematics, the concept of a measure is a generalization and formalization of geometrical measures (length, area, volume) and other common notions, such as magnitude, mass, and probability of events. These seemingly distinct concepts have many similarities and can often be treated together in a single mathematical context. Measures are foundational in probability theory, integration theory, and can be generalized to assume negative values, as with electrical charge. Far-reaching generalizations (such as spectral measures and projection-valued measures) of measure are widely used in quantum physics and physics in general.

The intuition behind this concept dates back to ancient Greece, when Archimedes tried to calculate the area of a circle.^[1] But it was not until the late 19th and early 20th centuries that measure theory became a branch of mathematics. The foundations of modern measure theory were laid in the works of Émile Borel, Henri Lebesgue, Nikolai Luzin, Johann Radon, Constantin Carathéodory, and Maurice Fréchet, among others.

Definition[edit]

Let ${\displaystyle X}$ be a set and ${\displaystyle \Sigma }$a${\displaystyle \sigma }$-algebra over ${\displaystyle X.}$Aset function ${\displaystyle \mu }$ from ${\displaystyle \Sigma }$ to the extended real number line is called a measure if the following conditions hold:

• Non-negativity: For all ${\displaystyle E\in \Sigma ,\ \ \mu ($E)\geq 0.}
• ${\displaystyle \mu (\varnothing )=0.}$
• Countable additivity (or${\displaystyle \sigma }$-additivity): For all countable collections ${\displaystyle \{E_{k}\}_{k=1}^{\infty }}$ of pairwise disjoint sets in Σ,$${\displaystyle \mu \left(\bigcup _{k=1}^{\infty }E_{k}\right)=\sum _{k=1}^{\infty }\mu (E_{k}).}$$

If at least one set ${\displaystyle E}$ has finite measure, then the requirement ${\displaystyle \mu (\varnothing )=0}$ is met automatically due to countable additivity: $${\displaystyle \mu ($$E)=\mu (E\cup \varnothing )=\mu (E)+\mu (\varnothing ),} and therefore ${\displaystyle \mu (\varnothing )=0.}$

If the condition of non-negativity is dropped, and ${\displaystyle \mu }$ takes on at most one of the values of ${\displaystyle \pm \infty ,}$ then ${\displaystyle \mu }$ is called a signed measure.

The pair ${\displaystyle (X,\Sigma )}$ is called a measurable space, and the members of ${\displaystyle \Sigma }$ are called measurable sets.

Atriple ${\displaystyle (X,\Sigma ,\mu )}$ is called a measure space. A probability measure is a measure with total measure one – that is, ${\displaystyle \mu ($X)=1.} Aprobability space is a measure space with a probability measure.

For measure spaces that are also topological spaces various compatibility conditions can be placed for the measure and the topology. Most measures met in practice in analysis (and in many cases also in probability theory) are Radon measures. Radon measures have an alternative definition in terms of linear functionals on the locally convex topological vector spaceofcontinuous functions with compact support. This approach is taken by Bourbaki (2004) and a number of other sources. For more details, see the article on Radon measures.

Instances[edit]

Some important measures are listed here.

• The counting measure is defined by ${\displaystyle \mu ($S)} = number of elements in ${\displaystyle S.}$
• The Lebesgue measureon${\displaystyle \mathbb {R} }$ is a complete translation-invariant measure on a σ-algebra containing the intervalsin${\displaystyle \mathbb {R} }$ such that ${\displaystyle \mu ([0,1])=1}$; and every other measure with these properties extends the Lebesgue measure.
• Circular angle measure is invariant under rotation, and hyperbolic angle measure is invariant under squeeze mapping.
• The Haar measure for a locally compact topological group is a generalization of the Lebesgue measure (and also of counting measure and circular angle measure) and has similar uniqueness properties.
• The Hausdorff measure is a generalization of the Lebesgue measure to sets with non-integer dimension, in particular, fractal sets.
• Every probability space gives rise to a measure which takes the value 1 on the whole space (and therefore takes all its values in the unit interval [0, 1]). Such a measure is called a probability measureordistribution. See the list of probability distributions for instances.
• The Dirac measure δ_a (cf. Dirac delta function) is given by δ_a(S) = χ_S(a), where χ_S is the indicator functionof${\displaystyle S.}$ The measure of a set is 1 if it contains the point ${\displaystyle a}$ and 0 otherwise.

Other 'named' measures used in various theories include: Borel measure, Jordan measure, ergodic measure, Gaussian measure, Baire measure, Radon measure, Young measure, and Loeb measure.

In physics an example of a measure is spatial distribution of mass (see for example, gravity potential), or another non-negative extensive property, conserved (see conservation law for a list of these) or not. Negative values lead to signed measures, see "generalizations" below.

• Liouville measure, known also as the natural volume form on a symplectic manifold, is useful in classical statistical and Hamiltonian mechanics.
• Gibbs measure is widely used in statistical mechanics, often under the name canonical ensemble.

Measure theory is used in machine learning. One example is the Flow Induced Probability Measure in GFlowNet.^[2]

Basic properties[edit]

Let ${\displaystyle \mu }$ be a measure.

Monotonicity[edit]

If${\displaystyle E_{1}}$ and ${\displaystyle E_{2}}$ are measurable sets with ${\displaystyle E_{1}\subseteq E_{2}}$ then $${\displaystyle \mu (E_{1})\leq \mu (E_{2}).}$$

Measure of countable unions and intersections[edit]

Countable subadditivity[edit]

For any countable sequence ${\displaystyle E_{1},E_{2},E_{3},\ldots }$ of (not necessarily disjoint) measurable sets ${\displaystyle E_{n}}$in${\displaystyle \Sigma :}$ $${\displaystyle \mu \left(\bigcup _{i=1}^{\infty }E_{i}\right)\leq \sum _{i=1}^{\infty }\mu (E_{i}).}$$

Continuity from below[edit]

If${\displaystyle E_{1},E_{2},E_{3},\ldots }$ are measurable sets that are increasing (meaning that ${\displaystyle E_{1}\subseteq E_{2}\subseteq E_{3}\subseteq \ldots }$) then the union of the sets ${\displaystyle E_{n}}$ is measurable and $${\displaystyle \mu \left(\bigcup _{i=1}^{\infty }E_{i}\right)~=~\lim _{i\to \infty }\mu (E_{i})=\sup _{i\geq 1}\mu (E_{i}).}$$

Continuity from above[edit]

If${\displaystyle E_{1},E_{2},E_{3},\ldots }$ are measurable sets that are decreasing (meaning that ${\displaystyle E_{1}\supseteq E_{2}\supseteq E_{3}\supseteq \ldots }$) then the intersection of the sets ${\displaystyle E_{n}}$ is measurable; furthermore, if at least one of the ${\displaystyle E_{n}}$ has finite measure then $${\displaystyle \mu \left(\bigcap _{i=1}^{\infty }E_{i}\right)=\lim _{i\to \infty }\mu (E_{i})=\inf _{i\geq 1}\mu (E_{i}).}$$

This property is false without the assumption that at least one of the ${\displaystyle E_{n}}$ has finite measure. For instance, for each ${\displaystyle n\in \mathbb {N} ,}$ let ${\displaystyle E_{n}=[n,\infty )\subseteq \mathbb {R} ,}$ which all have infinite Lebesgue measure, but the intersection is empty.

Other properties[edit]

Completeness[edit]

A measurable set ${\displaystyle X}$ is called a null setif${\displaystyle \mu ($X)=0.} A subset of a null set is called a negligible set. A negligible set need not be measurable, but every measurable negligible set is automatically a null set. A measure is called complete if every negligible set is measurable.

A measure can be extended to a complete one by considering the σ-algebra of subsets ${\displaystyle Y}$ which differ by a negligible set from a measurable set ${\displaystyle X,}$ that is, such that the symmetric differenceof${\displaystyle X}$ and ${\displaystyle Y}$ is contained in a null set. One defines ${\displaystyle \mu ($Y)} to equal ${\displaystyle \mu ($X).}

"Dropping the Edge"[edit]

If${\displaystyle f:X\to [0,+\infty ]}$is${\displaystyle (\Sigma ,{\cal {B}}([0,+\infty ]))}$-measurable, then $${\displaystyle \mu \{x\in X:f($$x)\geq t\}=\mu \{x\in X:f(x)>t\}} for almost all ${\displaystyle t\in [-\infty ,\infty ].}$^[3] This property is used in connection with Lebesgue integral.

If${\displaystyle t}$ is such that ${\displaystyle \mu \{x\in X:f($x)>t\}=+\infty } then monotonicity implies $${\displaystyle \mu \{x\in X:f($$x)\geq t\}=+\infty ,} so that ${\displaystyle F($t)=G(t),} as required. If ${\displaystyle \mu \{x\in X:f($x)>t\}=+\infty } for all ${\displaystyle t}$ then we are done, so assume otherwise. Then there is a unique ${\displaystyle t_{0}\in \{-\infty \}\cup [0,+\infty )}$ such that ${\displaystyle F}$ is infinite to the left of ${\displaystyle t}$ (which can only happen when ${\displaystyle t_{0}\geq 0}$) and finite to the right. Arguing as above, ${\displaystyle \mu \{x\in X:f($x)\geq t\}=+\infty } when ${\displaystyle t<t_{0}.}$ Similarly, if ${\displaystyle t_{0}\geq 0}$ and ${\displaystyle F\left(t_{0}\right)=+\infty }$ then ${\displaystyle F\left(t_{0}\right)=G\left(t_{0}\right).}$

For ${\displaystyle t>t_{0},}$ let ${\displaystyle t_{n}}$ be a monotonically non-decreasing sequence converging to ${\displaystyle t.}$ The monotonically non-increasing sequences ${\displaystyle \{x\in X:f($x)>t_{n}\}} of members of ${\displaystyle \Sigma }$ has at least one finitely ${\displaystyle \mu }$-measurable component, and $${\displaystyle \{x\in X:f($$x)\geq t\}=\bigcap _{n}\{x\in X:f(x)>t_{n}\}.} Continuity from above guarantees that $${\displaystyle \mu \{x\in X:f($$x)\geq t\}=\lim _{t_{n}\uparrow t}\mu \{x\in X:f(x)>t_{n}\}.} The right-hand side ${\displaystyle \lim _{t_{n}\uparrow t}F\left(t_{n}\right)}$ then equals ${\displaystyle F($t)=\mu \{x\in X:f(x)>t\}} if${\displaystyle t}$ is a point of continuity of ${\displaystyle F.}$ Since ${\displaystyle F}$ is continuous almost everywhere, this completes the proof.

Additivity[edit]

Measures are required to be countably additive. However, the condition can be strengthened as follows. For any set ${\displaystyle I}$ and any set of nonnegative ${\displaystyle r_{i},i\in I}$ define: $${\displaystyle \sum _{i\in I}r_{i}=\sup \left\lbrace \sum _{i\in J}r_{i}:|J|<\infty ,J\subseteq I\right\rbrace .}$$ That is, we define the sum of the ${\displaystyle r_{i}}$ to be the supremum of all the sums of finitely many of them.

A measure ${\displaystyle \mu }$on${\displaystyle \Sigma }$is${\displaystyle \kappa }$-additive if for any ${\displaystyle \lambda <\kappa }$ and any family of disjoint sets ${\displaystyle X_{\alpha },\alpha <\lambda }$ the following hold: $${\displaystyle \bigcup _{\alpha \in \lambda }X_{\alpha }\in \Sigma }$$ $${\displaystyle \mu \left(\bigcup _{\alpha \in \lambda }X_{\alpha }\right)=\sum _{\alpha \in \lambda }\mu \left(X_{\alpha }\right).}$$ The second condition is equivalent to the statement that the ideal of null sets is ${\displaystyle \kappa }$-complete.

Sigma-finite measures[edit]

A measure space ${\displaystyle (X,\Sigma ,\mu )}$ is called finite if ${\displaystyle \mu ($X)} is a finite real number (rather than ${\displaystyle \infty }$). Nonzero finite measures are analogous to probability measures in the sense that any finite measure ${\displaystyle \mu }$ is proportional to the probability measure ${\displaystyle {\frac {1}{\mu ($X)}}\mu .} A measure ${\displaystyle \mu }$ is called σ-finiteif${\displaystyle X}$ can be decomposed into a countable union of measurable sets of finite measure. Analogously, a set in a measure space is said to have a σ-finite measure if it is a countable union of sets with finite measure.

For example, the real numbers with the standard Lebesgue measure are σ-finite but not finite. Consider the closed intervals ${\displaystyle [k,k+1]}$ for all integers ${\displaystyle k;}$ there are countably many such intervals, each has measure 1, and their union is the entire real line. Alternatively, consider the real numbers with the counting measure, which assigns to each finite set of reals the number of points in the set. This measure space is not σ-finite, because every set with finite measure contains only finitely many points, and it would take uncountably many such sets to cover the entire real line. The σ-finite measure spaces have some very convenient properties; σ-finiteness can be compared in this respect to the Lindelöf property of topological spaces.^{[original research?]} They can be also thought of as a vague generalization of the idea that a measure space may have 'uncountable measure'.

Strictly localizable measures[edit]

Semifinite measures[edit]

Let ${\displaystyle X}$ be a set, let ${\displaystyle {\cal {A}}}$ be a sigma-algebra on ${\displaystyle X,}$ and let ${\displaystyle \mu }$ be a measure on ${\displaystyle {\cal {A}}.}$ We say ${\displaystyle \mu }$issemifinite to mean that for all ${\displaystyle A\in \mu ^{\text{pre}}\{+\infty \},}$ ${\displaystyle {\cal {P}}($A)\cap \mu ^{\text{pre}}(\mathbb {R} _{>0})\neq \emptyset .} ^[4]

Semifinite measures generalize sigma-finite measures, in such a way that some big theorems of measure theory that hold for sigma-finite but not arbitrary measures can be extended with little modification to hold for semifinite measures. (To-do: add examples of such theorems; cf. the talk page.)

Basic examples[edit]

• Every sigma-finite measure is semifinite.
• Assume ${\displaystyle {\cal {A}}={\cal {P}}($X),} let ${\displaystyle f:X\to [0,+\infty ],}$ and assume ${\displaystyle \mu ($A)=\sum _{a\in A}f(a)} for all ${\displaystyle A\subseteq X.}$
  • We have that ${\displaystyle \mu }$ is sigma-finite if and only if ${\displaystyle f($x)<+\infty } for all ${\displaystyle x\in X}$ and ${\displaystyle f^{\text{pre}}(\mathbb {R} _{>0})}$ is countable. We have that ${\displaystyle \mu }$ is semifinite if and only if ${\displaystyle f($x)<+\infty } for all ${\displaystyle x\in X.}$^[5]
  • Taking ${\displaystyle f=X\times \{1\}}$ above (so that ${\displaystyle \mu }$ is counting measure on ${\displaystyle {\cal {P}}($X)} ), we see that counting measure on ${\displaystyle {\cal {P}}($X)} is
    • sigma-finite if and only if ${\displaystyle X}$ is countable; and
    • semifinite (without regard to whether ${\displaystyle X}$ is countable). (Thus, counting measure, on the power set ${\displaystyle {\cal {P}}($X)} of an arbitrary uncountable set ${\displaystyle X,}$ gives an example of a semifinite measure that is not sigma-finite.)
• Let ${\displaystyle d}$ be a complete, separable metric on ${\displaystyle X,}$ let ${\displaystyle {\cal {B}}}$ be the Borel sigma-algebra induced by ${\displaystyle d,}$ and let ${\displaystyle s\in \mathbb {R} _{>0}.}$ Then the Hausdorff measure ${\displaystyle {\cal {H}}^{s}|{\cal {B}}}$ is semifinite.^[6]
• Let ${\displaystyle d}$ be a complete, separable metric on ${\displaystyle X,}$ let ${\displaystyle {\cal {B}}}$ be the Borel sigma-algebra induced by ${\displaystyle d,}$ and let ${\displaystyle s\in \mathbb {R} _{>0}.}$ Then the packing measure ${\displaystyle {\cal {H}}^{s}|{\cal {B}}}$ is semifinite.^[7]

Involved example[edit]

The zero measure is sigma-finite and thus semifinite. In addition, the zero measure is clearly less than or equal to ${\displaystyle \mu .}$ It can be shown there is a greatest measure with these two properties:

We say the semifinite partof${\displaystyle \mu }$ to mean the semifinite measure ${\displaystyle \mu _{\text{sf}}}$ defined in the above theorem. We give some nice, explicit formulas, which some authors may take as definition, for the semifinite part:

• ${\displaystyle \mu _{\text{sf}}=(\sup\{\mu ($B):B\in {\cal {P}}(A)\cap \mu ^{\text{pre}}(\mathbb {R} _{\geq 0})\})_{A\in {\cal {A}}}.} ^[8]
• ${\displaystyle \mu _{\text{sf}}=(\sup\{\mu (A\cap B):B\in \mu ^{\text{pre}}(\mathbb {R} _{\geq 0})\})_{A\in {\cal {A}}}\}.}$^[9]
• ${\displaystyle \mu _{\text{sf}}=\mu |_{\mu ^{\text{pre}}(\mathbb {R} _{>0})}\cup \{A\in {\cal {A}}:\sup\{\mu ($B):B\in {\cal {P}}(A)\}=+\infty \}\times \{+\infty \}\cup \{A\in {\cal {A}}:\sup\{\mu (B):B\in {\cal {P}}(A)\}<+\infty \}\times \{0\}.} ^[10]

Since ${\displaystyle \mu _{\text{sf}}}$ is semifinite, it follows that if ${\displaystyle \mu =\mu _{\text{sf}}}$ then ${\displaystyle \mu }$ is semifinite. It is also evident that if ${\displaystyle \mu }$ is semifinite then ${\displaystyle \mu =\mu _{\text{sf}}.}$

Non-examples[edit]

Every ${\displaystyle 0-\infty }$ measure that is not the zero measure is not semifinite. (Here, we say ${\displaystyle 0-\infty }$ measure to mean a measure whose range lies in ${\displaystyle \{0,+\infty \}}$: ${\displaystyle (\forall A\in {\cal {A}})(\mu ($A)\in \{0,+\infty \}).} ) Below we give examples of ${\displaystyle 0-\infty }$ measures that are not zero measures.

• Let ${\displaystyle X}$ be nonempty, let ${\displaystyle {\cal {A}}}$ be a ${\displaystyle \sigma }$-algebra on ${\displaystyle X,}$ let ${\displaystyle f:X\to \{0,+\infty \}}$ be not the zero function, and let ${\displaystyle \mu =(\sum _{x\in A}f($x))_{A\in {\cal {A}}}.} It can be shown that ${\displaystyle \mu }$ is a measure.
  • ${\displaystyle \mu =\{(\emptyset ,0)\}\cup ({\cal {A}}\setminus \{\emptyset \})\times \{+\infty \}.}$^[11]
    • ${\displaystyle X=\{0\},}$ ${\displaystyle {\cal {A}}=\{\emptyset ,X\},}$ ${\displaystyle \mu =\{(\emptyset ,0),(X,+\infty )\}.}$^[12]
• Let ${\displaystyle X}$ be uncountable, let ${\displaystyle {\cal {A}}}$ be a ${\displaystyle \sigma }$-algebra on ${\displaystyle X,}$ let ${\displaystyle {\cal {C}}=\{A\in {\cal {A}}:A{\text{ is countable}}\}}$ be the countable elements of ${\displaystyle {\cal {A}},}$ and let ${\displaystyle \mu ={\cal {C}}\times \{0\}\cup ({\cal {A}}\setminus {\cal {C}})\times \{+\infty \}.}$ It can be shown that ${\displaystyle \mu }$ is a measure.^[4]

Involved non-example[edit]

Measures that are not semifinite are very wild when restricted to certain sets.^{[Note 1]} Every measure is, in a sense, semifinite once its ${\displaystyle 0-\infty }$ part (the wild part) is taken away.

— A. Mukherjea and K. Pothoven, Real and Functional Analysis, Part A: Real Analysis (1985)

We say the ${\displaystyle \mathbf {0-\infty } }$ partof${\displaystyle \mu }$ to mean the measure ${\displaystyle \mu _{0-\infty }}$ defined in the above theorem. Here is an explicit formula for ${\displaystyle \mu _{0-\infty }}$: ${\displaystyle \mu _{0-\infty }=(\sup\{\mu ($B)-\mu _{\text{sf}}(B):B\in {\cal {P}}(A)\cap \mu _{\text{sf}}^{\text{pre}}(\mathbb {R} _{\geq 0})\})_{A\in {\cal {A}}}.}

Results regarding semifinite measures[edit]

• Let ${\displaystyle \mathbb {F} }$be${\displaystyle \mathbb {R} }$or${\displaystyle \mathbb {C} ,}$ and let ${\displaystyle T:L_{\mathbb {F} }^{\infty }(\mu )\to \left(L_{\mathbb {F} }^{1}(\mu )\right)^{*}:g\mapsto T_{g}=\left(\int fgd\mu \right)_{f\in L_{\mathbb {F} }^{1}(\mu )}.}$ Then ${\displaystyle \mu }$ is semifinite if and only if ${\displaystyle T}$ is injective.^[15][16] (This result has import in the study of the dual space of ${\displaystyle L^{1}=L_{\mathbb {F} }^{1}(\mu )}$.)
• Let ${\displaystyle \mathbb {F} }$be${\displaystyle \mathbb {R} }$or${\displaystyle \mathbb {C} ,}$ and let ${\displaystyle {\cal {T}}}$ be the topology of convergence in measure on ${\displaystyle L_{\mathbb {F} }^{0}(\mu ).}$ Then ${\displaystyle \mu }$ is semifinite if and only if ${\displaystyle {\cal {T}}}$ is Hausdorff.^[17][18]
• (Johnson) Let ${\displaystyle X}$ be a set, let ${\displaystyle {\cal {A}}}$ be a sigma-algebra on ${\displaystyle X,}$ let ${\displaystyle \mu }$ be a measure on ${\displaystyle {\cal {A}},}$ let ${\displaystyle Y}$ be a set, let ${\displaystyle {\cal {B}}}$ be a sigma-algebra on ${\displaystyle Y,}$ and let ${\displaystyle \nu }$ be a measure on ${\displaystyle {\cal {B}}.}$If${\displaystyle \mu ,\nu }$ are both not a ${\displaystyle 0-\infty }$ measure, then both ${\displaystyle \mu }$ and ${\displaystyle \nu }$ are semifinite if and only if ${\displaystyle (\mu \times _{\text{cld}}\nu )}$${\displaystyle (A\times B)=\mu ($A)\nu (B)} for all ${\displaystyle A\in {\cal {A}}}$ and ${\displaystyle B\in {\cal {B}}.}$ (Here, ${\displaystyle \mu \times _{\text{cld}}\nu }$ is the measure defined in Theorem 39.1 in Berberian '65.^[19])